Write the quadratic equation in standard form: 6x-9=-5x^(2) Answer:

Move x^2 term: First, add 5x^2 to both sides of the equation to move the x^2 term to the left side. 6x - 9 + 5x^2 = -5x^2 + 5x^2 This simplifies to: 5x^2 + 6x - 9 = 0Standard form: Now, we have the quadratic equation in standard form, which is ax^2 + bx + c = 0. In this case, a = 5, b = 6, and c = -9.

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Write the quadratic equation in standard form:

6x-9=-5x^(2)
Answer:

Write the quadratic equation in standard form: $\newline$ $6 x-9=-5 x^{2}$ $\newline$ Answer:

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Algebra 2

Quadratic equation with complex roots

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Q. Write the quadratic equation in standard form:

\newline

6 x-9=-5 x^{2}

\newline

Answer:

Move $x^2$ term: First, add $5x^2$ to both sides of the equation to move the $x^2$ term to the left side. $\newline$ $6x - 9 + 5x^2 = -5x^2 + 5x^2$ $\newline$ This simplifies to: $\newline$ $5x^2 + 6x - 9 = 0$
Standard form: Now, we have the quadratic equation in standard form, which is $ax^2 + bx + c = 0$ . In this case, $a = 5$ , $b = 6$ , and $c = -9$ .