Write the quadratic equation in standard form: 5x^(2)+4x-16=-4 Answer:

Move and Add Terms: To write the equation in standard form, we need to move all terms to one side of the equation to set it equal to zero. So, we add 4 to both sides of the equation to isolate the zero on the right side. 5x^(2) + 4x - 16 + 4 = -4 + 4Simplify the Equation: Now, we simplify the equation by combining like terms. 5x^(2) + 4x - 16 + 4 = 0 5x^(2) + 4x - 12 = 0Identify Constants: We have now written the equation in standard form, which is ax^(2) + bx + c = 0, where a, b, and c are constants. In this case, a = 5, b = 4, and c = -12.Check for Accuracy: We check our work to ensure there are no mathematical errors. The original equation was 5x^(2) + 4x - 16 = -4. After adding 4 to both sides, we got 5x^(2) + 4x - 12 = 0, which is the correct standard form.

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Algebra 2

Quadratic equation with complex roots

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Q. Write the quadratic equation in standard form:

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5 x^{2}+4 x-16=-4

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Answer:

Move and Add Terms: To write the equation in standard form, we need to move all terms to one side of the equation to set it equal to zero. $\newline$ So, we add $4$ to both sides of the equation to isolate the zero on the right side. $\newline$ $5x^{2} + 4x - 16 + 4 = -4 + 4$
Simplify the Equation: Now, we simplify the equation by combining like terms. $\newline$ $5x^{2} + 4x - 16 + 4 = 0$ $\newline$ $5x^{2} + 4x - 12 = 0$
Identify Constants: We have now written the equation in standard form, which is $ax^{2} + bx + c = 0$ , where $a$ , $b$ , and $c$ are constants. $\newline$ In this case, $a = 5$ , $b = 4$ , and $c = -12$ .
Check for Accuracy: We check our work to ensure there are no mathematical errors. The original equation was $5x^{2} + 4x - 16 = -4$ . After adding $4$ to both sides, we got $5x^{2} + 4x - 12 = 0$ , which is the correct standard form.