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Write the log equation as an exponential equation. You do not need to solve for
x.

log_((x+5))(2x)=(6)/(7)
Answer:

Write the log equation as an exponential equation. You do not need to solve for $\mathrm{x}$ . $\newline$ $\log _{(x+5)}(2 x)=\frac{6}{7}$ $\newline$ Answer:

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Quotient property of logarithms

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for

\mathrm{x}

.

\newline

\log _{(x+5)}(2 x)=\frac{6}{7}

\newline

Answer:

Define Logarithmic Equation: The logarithmic equation given is $\log_{(x+5)}(2x) = \frac{6}{7}$ . To convert this to an exponential equation, we use the definition of a logarithm: if $\log_b(a) = c$ , then $b^c = a$ . Here, $b$ is the base of the logarithm, $a$ is the argument, and $c$ is the logarithm result.
Convert to Exponential Equation: Applying the definition to our equation, we have $x+5$ as the base, $2x$ as the argument, and $\frac{6}{7}$ as the result. Therefore, the exponential form of the equation is $(x+5)^{\left(\frac{6}{7}\right)} = 2x$ .

More problems from Quotient property of logarithms

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x

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\newline

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Question

g(t) = 3^t

change over the interval from

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g(t)

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g(t)

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g(t)

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g(t)

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Question

f(x)

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\newline

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f(x)

\newline

\newline

f(x) = 6x

\newline

f(x) = 6^x

\newline

f(x) = \frac{1}{6^x}

\newline

f(x) = \frac{x}{6}

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