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Write the log equation as an exponential equation. You do not need to solve for 
x.

log(x^(2)+3x-6)=2
Answer:

Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog(x2+3x6)=2 \log \left(x^{2}+3 x-6\right)=2 \newlineAnswer:

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog(x2+3x6)=2 \log \left(x^{2}+3 x-6\right)=2 \newlineAnswer:
  1. Identify base, exponent, result: Identify the base bb, the exponent yy, and the result xx in the logarithmic equation log(x2+3x6)=2\log(x^{2}+3x-6)=2. In a logarithmic equation of the form logb(x)=y\log_b(x) = y, bb is the base, xx is the result, and yy is the exponent. Here, the base is understood to be 1010 because it is not written, so b=10b = 10, yy00, and the result is the expression yy11.
  2. Convert to exponential form: Convert the logarithmic equation to its equivalent exponential form using the relationship by=xb^y = x. Substitute b=10b = 10 and y=2y = 2 into the equation to get 102=x2+3x610^2 = x^2+3x-6.
  3. Write final exponential equation: Write the final exponential equation.\newlineThe exponential form of the given logarithmic equation log(x2+3x6)=2\log(x^{2}+3x-6)=2 is 102=x2+3x610^{2} = x^{2}+3x-6.

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