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Write the log equation as an exponential equation. You do not need to solve for
x.

ln(x^(2)-2x+7)=(9)/(5)
Answer:

Write the log equation as an exponential equation. You do not need to solve for $\mathrm{x}$ . $\newline$ $\ln \left(x^{2}-2 x+7\right)=\frac{9}{5}$ $\newline$ Answer:

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Convert between exponential and logarithmic form: all bases

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for

\mathrm{x}

.

\newline

\ln \left(x^{2}-2 x+7\right)=\frac{9}{5}

\newline

Answer:

Identify Base and Components: Identify the base of the natural logarithm and the components of the equation. $\newline$ The natural logarithm $\ln$ has a base of $e$ , where $e$ is the mathematical constant approximately equal to $2.71828$ . $\newline$ In the equation $\ln(x^{2}-2x+7)=\frac{9}{5}$ , we have: $\newline$ Base ( $b$ ) = $e$ $\newline$ Exponent ( $y$ ) = $\frac{9}{5}$ $\newline$ Argument ( $x$ ) = $e$ $0$
Convert to Exponential Form: Convert the logarithmic equation to exponential form. $\newline$ The general form of a logarithmic equation is $\ln(x) = y$ , which can be rewritten in exponential form as $e^y = x$ . $\newline$ Using this relationship, we can convert $\ln(x^{2}-2x+7)=\frac{9}{5}$ to its exponential form by raising $e$ to the power of $\frac{9}{5}$ to get the argument $x^{2}-2x+7$ . $\newline$ Exponential equation: $e^{\left(\frac{9}{5}\right)} = x^{2}-2x+7$

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