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Write the log equation as an exponential equation. You do not need to solve for
x.

log_(5)(x^(2)-2x+20)=5x
Answer:

Write the log equation as an exponential equation. You do not need to solve for $\mathrm{x}$ . $\newline$ $\log _{5}\left(x^{2}-2 x+20\right)=5 x$ $\newline$ Answer:

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Convert between exponential and logarithmic form: all bases

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for

\mathrm{x}

.

\newline

\log _{5}\left(x^{2}-2 x+20\right)=5 x

\newline

Answer:

Identify components: Identify the base $b$ , the argument $x$ , and the exponent $y$ in the logarithmic equation. $\newline$ The logarithmic equation is given as $\log_{5}(x^{2}-2x+20)=5x$ . Here, the base $b$ is $5$ , the argument $x$ is $x^{2}-2x+20$ , and the exponent $y$ is $5x$ .
Convert to exponential form: Convert the logarithmic equation to its equivalent exponential form. $\newline$ Using the definition of a logarithm, we can convert the equation $\log_{5}(x^{2}-2x+20)=5x$ to its exponential form by raising the base to the power of the exponent to get the argument. This gives us $5^{5x} = x^{2}-2x+20$ .
Write corresponding equation: Write down the exponential equation that corresponds to the given logarithmic equation. $\newline$ The exponential equation that corresponds to $\log_{5}(x^{2}-2x+20)=5x$ is $5^{5x} = x^{2}-2x+20$ .

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