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Write the log equation as an exponential equation. You do not need to solve for
x.

log_(2x)(4x+2)=2x+3
Answer:

Write the log equation as an exponential equation. You do not need to solve for $\mathrm{x}$ . $\newline$ $\log _{2 x}(4 x+2)=2 x+3$ $\newline$ Answer:

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Convert between exponential and logarithmic form

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for

\mathrm{x}

.

\newline

\log _{2 x}(4 x+2)=2 x+3

\newline

Answer:

Define logarithmic equation: The question_prompt: ＂What is the exponential form of the logarithmic equation $\log_{2x}(4x+2) = 2x+3$ ?＂ $\newline$ To convert a logarithmic equation to an exponential equation, we use the definition of a logarithm: if $\log_b(a) = c$ , then $b^c = a$ .
Convert to exponential form: Using the definition of a logarithm, we can rewrite the given logarithmic equation $\log_{2x}(4x+2) = 2x+3$ as an exponential equation. The base is $(2x)$ , the exponent is the right side of the equation $(2x+3)$ , and the result is the argument of the log $(4x+2)$ . So, the exponential form is $(2x)^{2x+3} = 4x+2$ .

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