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Write the log equation as an exponential equation. You do not need to solve for 
x.

log_(3x)(4x)=(4)/(9)
Answer:

Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog3x(4x)=49 \log _{3 x}(4 x)=\frac{4}{9} \newlineAnswer:

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog3x(4x)=49 \log _{3 x}(4 x)=\frac{4}{9} \newlineAnswer:
  1. Define Logarithmic Equation: The logarithmic equation given is log3x(4x)=49\log_{3x}(4x) = \frac{4}{9}. To convert a logarithmic equation to an exponential equation, we use the definition of a logarithm. The definition states that if logb(a)=c\log_b(a) = c, then bc=ab^c = a. Here, bb is the base of the logarithm, aa is the argument, and cc is the logarithm result.
  2. Apply Logarithmic Definition: Applying the definition to our equation, we have 3x3x as the base, 4x4x as the argument, and (4)/(9)(4)/(9) as the result. Therefore, the equivalent exponential equation is (3x)(4)/(9)=4x(3x)^{(4)/(9)} = 4x.
  3. Check for Errors: We check for any mathematical errors in the conversion process. The base 3x3x is raised to the power of the logarithm result (4)/(9)(4)/(9), and the argument 4x4x is correctly placed on the other side of the equation. There are no mathematical errors in this conversion.

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