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Write the log equation as an exponential equation. You do not need to solve for x. log_((x-1))(2)=x Answer:

Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog⁡(x−1)(2)=x \log _{(x-1)}(2)=x \newlineAnswer:

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Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog⁡(x−1)(2)=x \log _{(x-1)}(2)=x \newlineAnswer:
  1. Understand Relationship: Understand the relationship between logarithms and exponentials. The logarithmic equation log⁡b(a)=c\log_b(a) = c can be rewritten as an exponential equation bc=ab^c = a.
  2. Apply Relationship: Apply the relationship to the given equation.\newlineGiven the logarithmic equation log⁡(x−1)(2)=x\log_{(x-1)}(2)=x, we can rewrite it as an exponential equation using the relationship from Step 11.\newline(x−1)x=2(x - 1)^x = 2

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