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Write the log equation as an exponential equation. You do not need to solve for 
x.

log_(2x)(2)=(5)/(3)
Answer:

Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog2x(2)=53 \log _{2 x}(2)=\frac{5}{3} \newlineAnswer:

Full solution

Q. Write the log equation as an exponential equation. You do not need to solve for x \mathrm{x} .\newlinelog2x(2)=53 \log _{2 x}(2)=\frac{5}{3} \newlineAnswer:
  1. Define Logarithmic Equation: The logarithmic equation given is log2x(2)=53\log_{2x}(2) = \frac{5}{3}. To convert a logarithmic equation to an exponential equation, we use the definition of a logarithm. The definition states that if logb(a)=c\log_b(a) = c, then bc=ab^c = a. Here, bb is the base of the logarithm, aa is the argument, and cc is the logarithm result.
  2. Convert to Exponential Form: Using the definition of the logarithm, we can rewrite the given equation log2x(2)=53\log_{2x}(2) = \frac{5}{3} as an exponential equation. The base is 2x2x, the exponent will be the result of the logarithm which is 53\frac{5}{3}, and the result will be the argument of the logarithm which is 22. Therefore, the exponential form is (2x)53=2(2x)^{\frac{5}{3}} = 2.

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