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Write the expression below as a single logarithm in simplest form.

log_(b)6+log_(b)7
Answer: 
log_(b)(◻)

Write the expression below as a single logarithm in simplest form.\newlinelogb6+logb7 \log _{b} 6+\log _{b} 7 \newlineAnswer: logb() \log _{b}(\square)

Full solution

Q. Write the expression below as a single logarithm in simplest form.\newlinelogb6+logb7 \log _{b} 6+\log _{b} 7 \newlineAnswer: logb() \log _{b}(\square)
  1. Identify Property: Identify the property used to combine the sum of logarithms.\newlineThe sum of two logarithms with the same base can be combined using the product property of logarithms.\newlineProduct Property: logb(P)+logb(Q)=logb(P×Q)\log_b (P) + \log_b (Q) = \log_b (P \times Q)
  2. Apply Product Property: Apply the product property to combine logb6\log_{b}6 and logb7\log_{b}7. Using the product property, we can write the sum of logb6\log_{b}6 and logb7\log_{b}7 as a single logarithm of the product of 66 and 77.\newlinelogb6+logb7=logb(6×7)\log_{b}6 + \log_{b}7 = \log_{b}(6 \times 7)
  3. Calculate Product: Calculate the product of 66 and 77.\newlineTo find the value inside the logarithm, we multiply 66 by 77.\newline6×7=426 \times 7 = 42
  4. Write Final Expression: Write the final expression as a single logarithm.\newlineNow that we have the product, we can write the final expression as:\newlinelogb(42)\log_{b}(42)

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