Write the expression below as a single logarithm in simplest form. log_(b)9-log_(b)9 Answer: log_(b)(◻)

Identify Property: Identify the property used to combine the logarithms. The expression log_(b)9 - log_(b)9 involves the subtraction of two logarithms with the same base and the same argument. The property that applies here is that the logarithm of any number minus itself is zero. Calculation: log_(b)9 - log_(b)9 = 0Apply Property: Write the expression as a single logarithm. Since the result of the subtraction is zero, the expression as a single logarithm is simply the logarithm of 1, because the logarithm of 1 to any base is zero. Calculation: log_(b)(1) = 0

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Write the expression below as a single logarithm in simplest form.

log_(b)9-log_(b)9
Answer:
log_(b)(◻)

Write the expression below as a single logarithm in simplest form. $\newline$ $\log _{b} 9-\log _{b} 9$ $\newline$ Answer: $\log _{b}(\square)$

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Algebra 2

Quotient property of logarithms

Full solution

Q. Write the expression below as a single logarithm in simplest form.

\newline

\log _{b} 9-\log _{b} 9

\newline

Answer:

\log _{b}(\square)

Identify Property: Identify the property used to combine the logarithms. $\newline$ The expression $\log_{b}9 - \log_{b}9$ involves the subtraction of two logarithms with the same base and the same argument. $\newline$ The property that applies here is that the logarithm of any number minus itself is zero. $\newline$ Calculation: $\log_{b}9 - \log_{b}9 = 0$
Apply Property: Write the expression as a single logarithm. $\newline$ Since the result of the subtraction is zero, the expression as a single logarithm is simply the logarithm of $1$ , because the logarithm of $1$ to any base is zero. $\newline$ Calculation: $\log_{b}(1) = 0$