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Write the exponential equation in logarithmic form.\newlinee1≈2.718 e^1 \approx 2.718

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Full solution

Q. Write the exponential equation in logarithmic form.\newlinee1≈2.718 e^1 \approx 2.718
  1. Identify variables: Identify bb, xx, and yy. Compare e1≈2.718e^1 \approx 2.718 with by=xb^y = x. b=eb = e x=2.718x = 2.718 y=1y = 1
  2. Convert to logarithmic form: Convert the exponential equation to logarithmic form. Substitute b=eb = e, x=2.718x = 2.718, and y=1y = 1 in log⁡b(x)=y\log_b(x) = y. Logarithmic equation: ln⁡(2.718)≈1\ln(2.718) \approx 1
  3. Find missing value: Identify the missing value in ln⁡____≈1 \ln \_\_\_\_ \approx 1 . ln⁡(2.718)≈1 \ln(2.718) \approx 1 Missing value: 2.718 2.718

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