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Write the equation of the line that passes through the points 
(-6,-1) and 
(8,4). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.
Answer:

Write the equation of the line that passes through the points (6,1) (-6,-1) and (8,4) (8,4) . Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.\newlineAnswer:

Full solution

Q. Write the equation of the line that passes through the points (6,1) (-6,-1) and (8,4) (8,4) . Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.\newlineAnswer:
  1. Calculate slope: Calculate the slope mm of the line using the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the given points (6,1)(-6,-1) and (8,4)(8,4).
    m=4(1)8(6)m = \frac{4 - (-1)}{8 - (-6)}
    m=4+18+6m = \frac{4 + 1}{8 + 6}
    m=514m = \frac{5}{14}
  2. Choose point: Choose one of the points to use in the point-slope form equation. We will use the point (6,1)(-6,-1).
  3. Write point-slope equation: Write the equation of the line in point-slope form using the slope m=514m = \frac{5}{14} and the point (6,1)(-6,-1). The point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1).\newliney(1)=(514)(x(6))y - (-1) = \left(\frac{5}{14}\right)(x - (-6))\newliney+1=(514)(x+6)y + 1 = \left(\frac{5}{14}\right)(x + 6)
  4. Simplify equation: Simplify the equation by distributing the slope on the right side.\newliney+1=514x+5146y + 1 = \frac{5}{14}x + \frac{5}{14}\cdot6\newliney+1=514x+3014y + 1 = \frac{5}{14}x + \frac{30}{14}\newliney+1=514x+157y + 1 = \frac{5}{14}x + \frac{15}{7}
  5. Subtract 11: Subtract 11 from both sides to get the final point-slope form of the equation.\newliney=514x+1571y = \frac{5}{14}x + \frac{15}{7} - 1\newliney=514x+15777y = \frac{5}{14}x + \frac{15}{7} - \frac{7}{7}\newliney=514x+87y = \frac{5}{14}x + \frac{8}{7}

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