Write sqrt(-8) in simplest radical form. Answer:

Express as Product: Express sqrt(-8) as the product of square roots and sqrt(-1). sqrt(-8) = sqrt(-1 * 8) = sqrt(-1) * sqrt(8)Use Imaginary Unit: Express sqrt(-1) as the imaginary unit i and simplify sqrt(8). sqrt(-8) = sqrt(-1) * sqrt(8) = i * sqrt(4 * 2) = i * sqrt(4) * sqrt(2)Simplify Square Root: Simplify the square root of 4, which is a perfect square. sqrt(-8) = i * sqrt(4) * sqrt(2) = i * 2 * sqrt(2) = 2i * sqrt(2)

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Write
sqrt(-8) in simplest radical form.
Answer:

Write $\sqrt{-8}$ in simplest radical form. $\newline$ Answer:

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Algebra 2

Introduction to complex numbers

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Q. Write

\sqrt{-8}

in simplest radical form.

\newline

Answer:

Express as Product: Express $\sqrt{-8}$ as the product of square roots and $\sqrt{-1}$ . $\sqrt{-8} = \sqrt{-1 \times 8} = \sqrt{-1} \times \sqrt{8}$
Use Imaginary Unit: Express $\sqrt{-1}$ as the imaginary unit $i$ and simplify $\sqrt{8}$ . $\sqrt{-8} = \sqrt{-1} \times \sqrt{8} = i \times \sqrt{4 \times 2} = i \times \sqrt{4} \times \sqrt{2}$
Simplify Square Root: Simplify the square root of $4$ , which is a perfect square. $\sqrt{-8} = i \times \sqrt{4} \times \sqrt{2} = i \times 2 \times \sqrt{2} = 2i \times \sqrt{2}$