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Write an exponential function in the form 
y=ab^(x) that goes through the points 
(0,14) and 
(7,1792).
Answer:

Write an exponential function in the form y=abx y=a b^{x} that goes through the points (0,14) (0,14) and (7,1792) (7,1792) .\newlineAnswer:

Full solution

Q. Write an exponential function in the form y=abx y=a b^{x} that goes through the points (0,14) (0,14) and (7,1792) (7,1792) .\newlineAnswer:
  1. Find a Value: We need to find the values of aa and bb for the exponential function y=abxy=ab^{x} that passes through the points (0,14)(0,14) and (7,1792)(7,1792). We will use the first point (0,14)(0,14) to find the value of aa. Substitute x=0x=0 and y=14y=14 into the equation y=abxy=ab^{x}. bb00 Since any number raised to the power of bb11 is bb22, we have: bb33 Therefore, bb44.
  2. Use First Point: Now we will use the second point (7,1792)(7,1792) to find the value of bb. Substitute x=7x=7, y=1792y=1792, and a=14a=14 into the equation y=abxy=ab^{x}. 1792=14×b71792 = 14 \times b^7 To solve for bb, we divide both sides by 1414: 1792/14=b71792 / 14 = b^7 bb00 Now we need to find the bb11th root of bb22 to solve for bb. bb44 Calculating the bb11th root of bb22 gives us: bb77
  3. Use Second Point: We should check if b2b \approx 2 is a correct approximation by raising 22 to the power of 77 and see if it equals 128128.\newline27=1282^7 = 128\newlineSince 272^7 indeed equals 128128, our value for bb is correct.
  4. Check Approximation: Now that we have both aa and bb, we can write the exponential function.a=14a = 14 and b=2b = 2, so the function is:y=14×2xy = 14 \times 2^{x}

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