Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Write an equation of an exponential function that passes through the points (2,200)(2, 200) and (1,102.4)(-1, 102.4)

Full solution

Q. Write an equation of an exponential function that passes through the points (2,200)(2, 200) and (1,102.4)(-1, 102.4)
  1. Given Points: We are given two points (2,200)(2, 200) and (1,102.4)(-1, 102.4) through which an exponential function passes. The general form of an exponential function is y=abxy = ab^x, where aa is the initial value and bb is the base of the exponential function. We need to find the values of aa and bb.
  2. Create Equation 11: Let's use the first point 2,2002, 200 to create an equation. Substituting x=2x = 2 and y=200y = 200 into the exponential function y=abxy = ab^x, we get:200=ab2200 = ab^2
  3. Create Equation 22: Now, let's use the second point (1,102.4)(-1, 102.4) to create another equation. Substituting x=1x = -1 and y=102.4y = 102.4 into the exponential function y=abxy = ab^x, we get:\newline102.4=ab1102.4 = ab^{-1}
  4. Solve System of Equations: We now have a system of two equations with two unknowns:\newline11) 200=ab2200 = ab^2\newline22) 102.4=ab1102.4 = ab^{-1}\newlineWe can solve this system by dividing the second equation by the first equation to eliminate the variable aa.
  5. Divide Equations: Dividing the second equation by the first equation gives us:\newline(102.4/200)=(ab1)/(ab2)(102.4 / 200) = (ab^{-1}) / (ab^2)\newline0.512=1/b30.512 = 1/b^3\newlineNow we need to solve for bb.
  6. Solve for bb: To solve for bb, we take the cube root of both sides of the equation:\newlineb=(0.512)13b = (0.512)^{\frac{1}{3}}\newlineCalculating this gives us:\newlineb0.8b \approx 0.8
  7. Substitute for b: Now that we have the value of b, we can substitute it back into either of the original equations to solve for a. Let's use the first equation:\newline200=ab2200 = ab^2\newline200=a(0.8)2200 = a(0.8)^2\newline200=a(0.64)200 = a(0.64)
  8. Solve for a: To solve for a, we divide both sides by 0.640.64: \newlinea=2000.64a = \frac{200}{0.64}\newlinea312.5a \approx 312.5
  9. Final Exponential Function: We have found the values of aa and bb for the exponential function. The equation of the exponential function that passes through the points (2,200)(2, 200) and (1,102.4)(-1, 102.4) is:\newliney=312.5×0.8xy = 312.5 \times 0.8^x

More problems from Write a linear equation from two points