Q. Write an equation of an exponential function that passes through the points (2,200) and (−1,102.4)
Given Points: We are given two points (2,200) and (−1,102.4) through which an exponential function passes. The general form of an exponential function is y=abx, where a is the initial value and b is the base of the exponential function. We need to find the values of a and b.
Create Equation 1: Let's use the first point 2,200 to create an equation. Substituting x=2 and y=200 into the exponential function y=abx, we get:200=ab2
Create Equation 2: Now, let's use the second point (−1,102.4) to create another equation. Substituting x=−1 and y=102.4 into the exponential function y=abx, we get:102.4=ab−1
Solve System of Equations: We now have a system of two equations with two unknowns:1) 200=ab22) 102.4=ab−1We can solve this system by dividing the second equation by the first equation to eliminate the variable a.
Divide Equations: Dividing the second equation by the first equation gives us:(102.4/200)=(ab−1)/(ab2)0.512=1/b3Now we need to solve for b.
Solve for b: To solve for b, we take the cube root of both sides of the equation:b=(0.512)31Calculating this gives us:b≈0.8
Substitute for b: Now that we have the value of b, we can substitute it back into either of the original equations to solve for a. Let's use the first equation:200=ab2200=a(0.8)2200=a(0.64)
Solve for a: To solve for a, we divide both sides by 0.64: a=0.64200a≈312.5
Final Exponential Function: We have found the values of a and b for the exponential function. The equation of the exponential function that passes through the points (2,200) and (−1,102.4) is:y=312.5×0.8x
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