Write a polynomial of least degree with roots -6 and -2. Write your answer using the variable x and in standard form with a leading coefficient of 1. ______

Identify root -6 factor: The factor for the root -6 is (x - (-6)) which simplifies to (x + 6).Identify root -2 factor: The factor for the root -2 is (x - (-2)) which simplifies to (x + 2).Multiply factors: Now, we multiply the factors (x + 6) and (x + 2) to get the polynomial. (x + 6)(x + 2) = x^2 + 2x + 6x + 12Combine like terms: Combine like terms to get the polynomial in standard form. x^2 + 2x + 6x + 12 = x^2 + 8x + 12

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Write a polynomial of least degree with roots $-6$ and $-2$ . $\newline$ Write your answer using the variable $x$ and in standard form with a leading coefficient of $1$ .

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Write a polynomial from its roots

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Q. Write a polynomial of least degree with roots

-6

and

-2

\newline

Write your answer using the variable

x

and in standard form with a leading coefficient of

1

Identify root $-6$ factor: The factor for the root $-6$ is $(x - (-6))$ which simplifies to $(x + 6)$ .
Identify root $-2$ factor: The factor for the root $-2$ is $(x - (-2))$ which simplifies to $(x + 2)$ .
Multiply factors: Now, we multiply the factors $(x + 6)$ and $(x + 2)$ to get the polynomial. $(x + 6)(x + 2) = x^2 + 2x + 6x + 12$
Combine like terms: Combine like terms to get the polynomial in standard form. $\newline$ $x^2 + 2x + 6x + 12 = x^2 + 8x + 12$