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Which value of 
x satisfies the equation 
(3)/(2)(x+(6)/(5))=(93)/(10) ?
5
4

-5

-4

Which value of x x satisfies the equation 32(x+65)=9310 \frac{3}{2}\left(x+\frac{6}{5}\right)=\frac{93}{10} ?\newline55\newline44\newline5 -5 \newline4 -4

Full solution

Q. Which value of x x satisfies the equation 32(x+65)=9310 \frac{3}{2}\left(x+\frac{6}{5}\right)=\frac{93}{10} ?\newline55\newline44\newline5 -5 \newline4 -4
  1. Isolate variable xx: First, we need to isolate the variable xx in the equation 32(x+65)=9310\frac{3}{2}(x+\frac{6}{5})=\frac{93}{10}. To do this, we will start by multiplying both sides of the equation by the reciprocal of 32\frac{3}{2}, which is 23\frac{2}{3}, to cancel out the 32\frac{3}{2} on the left side.
  2. Multiply by reciprocal: Perform the multiplication on both sides of the equation: (23)×(32)(x+(65))=(23)×(9310)(\frac{2}{3}) \times (\frac{3}{2})(x + (\frac{6}{5})) = (\frac{2}{3}) \times (\frac{93}{10}).
  3. Simplify both sides: On the left side, (23)×(32)(\frac{2}{3}) \times (\frac{3}{2}) simplifies to 11, leaving us with x+(65)x + (\frac{6}{5}). On the right side, we multiply (23)(\frac{2}{3}) by (9310)(\frac{93}{10}) to get (18630)(\frac{186}{30}), which simplifies to (315)(\frac{31}{5}). So, we have x+(65)=(315)x + (\frac{6}{5}) = (\frac{31}{5}).
  4. Subtract (65):</b>Next,wesubtract$(65)(\frac{6}{5}):</b> Next, we subtract \$(\frac{6}{5}) from both sides of the equation to solve for x.x.\newlinex+(65)(65)=(315)(65).x + (\frac{6}{5}) - (\frac{6}{5}) = (\frac{31}{5}) - (\frac{6}{5}).
  5. Solve for x: After subtracting, we get x=31565x = \frac{31}{5} - \frac{6}{5}.
  6. Subtract fractions: Now, we subtract the fractions on the right side: (315)(65)=(255)(\frac{31}{5}) - (\frac{6}{5}) = (\frac{25}{5}).
  7. Final result: The fraction (255)(\frac{25}{5}) simplifies to 55, so we have x=5x = 5.

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