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Which value of 
x satisfies the equation 
(1)/(3)(x-(1)/(2))=-(1)/(2) ?
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Which value of x x satisfies the equation 13(x12)=12 \frac{1}{3}\left(x-\frac{1}{2}\right)=-\frac{1}{2} ?\newline11\newline22\newline2 -2 \newline1 -1

Full solution

Q. Which value of x x satisfies the equation 13(x12)=12 \frac{1}{3}\left(x-\frac{1}{2}\right)=-\frac{1}{2} ?\newline11\newline22\newline2 -2 \newline1 -1
  1. Isolate variable x: First, we need to isolate the variable xx in the equation 13(x12)=12\frac{1}{3}(x-\frac{1}{2})=-\frac{1}{2}. To do this, we can start by multiplying both sides of the equation by 33 to get rid of the fraction on the left side.\newline13(x12)×3=12×3\frac{1}{3}(x-\frac{1}{2}) \times 3 = -\frac{1}{2} \times 3
  2. Multiply by 33: After multiplying both sides by 33, we get:\newlinex12=32x - \frac{1}{2} = -\frac{3}{2}\newlineNow, we need to solve for xx by adding 12\frac{1}{2} to both sides of the equation.
  3. Add (1)/(2)(1)/(2): Adding (1)/(2)(1)/(2) to both sides gives us:\newlinex12+12=32+12x - \frac{1}{2} + \frac{1}{2} = -\frac{3}{2} + \frac{1}{2}\newlineThis simplifies to:\newlinex=32+12x = -\frac{3}{2} + \frac{1}{2}
  4. Combine fractions: Now we combine the fractions on the right side of the equation:\newlinex=22+12x = \frac{-2}{2} + \frac{1}{2}\newlinex=12x = \frac{-1}{2}
  5. Final value of x: We have found the value of x that satisfies the equation:\newlinex=12x = -\frac{1}{2}\newlineHowever, this value is not listed in the options provided. We need to check our calculations to see if there was an error.

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