Which value of h makes (8+h)/(10)=1 a true statement? Choose 1 answer: (A) h=1 (B) h=2 (c) h=3 (D) h=4

Multiply both sides by 10: To find the value of h that makes the equation true, we need to isolate h on one side of the equation. We start by multiplying both sides of the equation by 10 to eliminate the denominator. (8+h)/10 * 10 = 1 * 10Simplify the equation: After multiplying both sides by 10, we get: 8 + h = 10Subtract 8 from both sides: Now, we subtract 8 from both sides to solve for h. 8 + h - 8 = 10 - 8Solve for h: This simplifies to: h = 2Check the solution: We check our solution by substituting h back into the original equation to see if it makes the equation true. (8+2)/10 = 1 10/10 = 1 1 = 1

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Let’s check out your problem:

Which value of
h makes
(8+h)/(10)=1 a true statement?
Choose 1 answer:
(A)
h=1
(B)
h=2
(c)
h=3
(D)
h=4

Which value of $h$ makes $\frac{8+h}{10}=1$ a true statement? $\newline$ Choose $1$ answer: $\newline$ (A) $h=1$ $\newline$ (B) $h=2$ $\newline$ (C) $h=3$ $\newline$ (D) $h=4$

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Math Problems

Grade 6

Inequalities with decimal multiplication

Full solution

Q. Which value of

h

makes

\frac{8+h}{10}=1

a true statement?

\newline

Choose

1

answer:

\newline

(A)

h=1

\newline

(B)

h=2

\newline

(C)

h=3

\newline

(D)

h=4

Multiply both sides by $10$ : To find the value of $h$ that makes the equation true, we need to isolate $h$ on one side of the equation. We start by multiplying both sides of the equation by $10$ to eliminate the denominator. $\newline$ $(8+h)/10 \times 10 = 1 \times 10$
Simplify the equation: After multiplying both sides by $10$ , we get: $8 + h = 10$
Subtract $8$ from both sides: Now, we subtract $8$ from both sides to solve for $h$ . $8 + h - 8 = 10 - 8$
Solve for h: This simplifies to: $h = 2$
Check the solution: We check our solution by substituting $h$ back into the original equation to see if it makes the equation true. $\newline$ $(8+2)/10 = 1$ $\newline$ $10/10 = 1$ $\newline$ $1 = 1$