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Let’s check out your problem:
Which sign makes the statement true?
\newline
6
12
\frac{6}{12}
12
6
?
\text{?}
?
3
12
+
1
4
\frac{3}{12} + \frac{1}{4}
12
3
+
4
1
\newline
Choices:
\newline
(A) >
\newline
(B) <
\newline
(C)
=
=
=
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Home
Math Problems
Grade 7
Inequalities with addition and subtraction of fractions and mixed numbers
Full solution
Q.
Which sign makes the statement true?
\newline
6
12
\frac{6}{12}
12
6
?
\text{?}
?
3
12
+
1
4
\frac{3}{12} + \frac{1}{4}
12
3
+
4
1
\newline
Choices:
\newline
(A)
>
>
>
\newline
(B)
<
<
<
\newline
(C)
=
=
=
Simplify
Fraction
:
Simplify
6
12
\frac{6}{12}
12
6
to its lowest terms. Calculation:
6
12
=
1
2
.
\frac{6}{12} = \frac{1}{2}.
12
6
=
2
1
.
Convert to Common Denominator:
Convert
1
4
\frac{1}{4}
4
1
to a fraction with a denominator of
12
12
12
for easy addition. Calculation:
1
4
=
3
12
\frac{1}{4} = \frac{3}{12}
4
1
=
12
3
.
Add
Fractions
:
Add
3
12
\frac{3}{12}
12
3
and
3
12
\frac{3}{12}
12
3
to find the sum. Calculation:
3
12
+
3
12
=
6
12
\frac{3}{12} + \frac{3}{12} = \frac{6}{12}
12
3
+
12
3
=
12
6
.
Compare Fractions:
Compare
1
2
\frac{1}{2}
2
1
and
6
12
\frac{6}{12}
12
6
. Since
1
2
\frac{1}{2}
2
1
is equal to
6
12
\frac{6}{12}
12
6
, the correct sign is '='.
More problems from Inequalities with addition and subtraction of fractions and mixed numbers
Question
Find `x` value
\newline
2
x
−
2
=
0
2x-2=0
2
x
−
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=
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2
x
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\newline
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6
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Question
Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
×
(
6
1
)
=
\newline
Submit
\newline
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Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
.
x.
x
.
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Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
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Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
2
6^{3} \cdot 6^{2}
6
3
⋅
6
2
\newline
Answer:
6
□
6 ^\square
6
□
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Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
−
2
=
79
9 z-2=79
9
z
−
2
=
79
\newline
3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
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Posted 8 months ago
Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
\newline
6
6
6
\newline
17
17
17
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