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Let’s check out your problem:
Which sign makes the statement true?
\newline
5
11
\frac{5}{11}
11
5
?
\text{?}
?
10
11
−
4
11
\frac{10}{11} - \frac{4}{11}
11
10
−
11
4
\newline
Choices:
\newline
(A) >
\newline
(B) <
\newline
(C)
=
=
=
View step-by-step help
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Math Problems
Grade 7
Inequalities with addition and subtraction of fractions and mixed numbers
Full solution
Q.
Which sign makes the statement true?
\newline
5
11
\frac{5}{11}
11
5
?
\text{?}
?
10
11
−
4
11
\frac{10}{11} - \frac{4}{11}
11
10
−
11
4
\newline
Choices:
\newline
(A)
>
>
>
\newline
(B)
<
<
<
\newline
(C)
=
=
=
Calculate Result:
Calculate the result of
10
11
\frac{10}{11}
11
10
minus
4
11
\frac{4}{11}
11
4
.
\newline
10
11
−
4
11
=
10
−
4
11
=
6
11
\frac{10}{11} - \frac{4}{11} = \frac{10 - 4}{11} = \frac{6}{11}
11
10
−
11
4
=
11
10
−
4
=
11
6
Compare
Fractions
:
Compare
5
11
\frac{5}{11}
11
5
with
6
11
\frac{6}{11}
11
6
to determine the correct sign.
\newline
5
11
?
6
11
\frac{5}{11} \, ? \, \frac{6}{11}
11
5
?
11
6
\newline
Since
5
11
\frac{5}{11}
11
5
is less than
6
11
\frac{6}{11}
11
6
, the correct sign is <.
More problems from Inequalities with addition and subtraction of fractions and mixed numbers
Question
Find `x` value
\newline
2
x
−
2
=
0
2x-2=0
2
x
−
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2
x
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Question
Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
×
(
6
1
)
=
\newline
Submit
\newline
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Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
.
x.
x
.
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Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
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Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
2
6^{3} \cdot 6^{2}
6
3
⋅
6
2
\newline
Answer:
6
□
6 ^\square
6
□
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Posted 8 months ago
Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
−
2
=
79
9 z-2=79
9
z
−
2
=
79
\newline
3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
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Posted 8 months ago
Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
\newline
6
6
6
\newline
17
17
17
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