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Which recursive sequence would produce the sequence 
5,14,32,dots ?

a_(1)=5 and 
a_(n)=4a_(n-1)+2

a_(1)=5 and 
a_(n)=-a_(n-1)+3

a_(1)=5 and 
a_(n)=2a_(n-1)+4

a_(1)=5 and 
a_(n)=3a_(n-1)-1

Which recursive sequence would produce the sequence 5,14,32, 5,14,32, \ldots ?\newlinea1=5 a_{1}=5 and an=4an1+2 a_{n}=4 a_{n-1}+2 \newlinea1=5 a_{1}=5 and an=an1+3 a_{n}=-a_{n-1}+3 \newlinea1=5 a_{1}=5 and an=2an1+4 a_{n}=2 a_{n-1}+4 \newlinea1=5 a_{1}=5 and an=3an11 a_{n}=3 a_{n-1}-1

Full solution

Q. Which recursive sequence would produce the sequence 5,14,32, 5,14,32, \ldots ?\newlinea1=5 a_{1}=5 and an=4an1+2 a_{n}=4 a_{n-1}+2 \newlinea1=5 a_{1}=5 and an=an1+3 a_{n}=-a_{n-1}+3 \newlinea1=5 a_{1}=5 and an=2an1+4 a_{n}=2 a_{n-1}+4 \newlinea1=5 a_{1}=5 and an=3an11 a_{n}=3 a_{n-1}-1
  1. Calculate Second Term: To determine which recursive sequence produces the given sequence, we will calculate the second term using each of the provided recursive formulas and compare it to the second term of the given sequence, which is 1414.
  2. Try Formula 11: First, let's try the recursive formula a1=5a_{1}=5 and an=4an1+2a_{n}=4a_{n-1}+2. We start with a1=5a_{1}=5 and calculate a2a_{2}. \newlinea2=4a1+2=4×5+2=20+2=22a_{2} = 4a_{1} + 2 = 4\times5 + 2 = 20 + 2 = 22. \newlineThis does not match the second term of the given sequence, which is 1414.
  3. Try Formula 22: Next, let's try the recursive formula a1=5a_{1}=5 and an=an1+3a_{n}=-a_{n-1}+3. We start with a1=5a_{1}=5 and calculate a2a_{2}. \newlinea2=a1+3=5+3=2a_{2} = -a_{1} + 3 = -5 + 3 = -2. \newlineThis does not match the second term of the given sequence, which is 1414.
  4. Try Formula 33: Now, let's try the recursive formula a1=5a_{1}=5 and an=2an1+4a_{n}=2a_{n-1}+4. We start with a1=5a_{1}=5 and calculate a2a_{2}. a2=2a1+4=2×5+4=10+4=14a_{2} = 2a_{1} + 4 = 2\times5 + 4 = 10 + 4 = 14. This matches the second term of the given sequence, which is 1414. However, we need to verify that the third term also matches before we can conclude this is the correct formula.
  5. Verify Formula 33: Using the same formula a1=5a_{1}=5 and an=2an1+4a_{n}=2a_{n-1}+4, let's calculate a3a_{3}.a3=2a2+4=2×14+4=28+4=32a_{3} = 2a_{2} + 4 = 2\times14 + 4 = 28 + 4 = 32.This matches the third term of the given sequence, which is 3232. Therefore, this recursive formula produces the given sequence.
  6. Check Formula 44: Finally, for completeness, let's check the last recursive formula a1=5a_{1}=5 and an=3an11a_{n}=3a_{n-1}-1. We start with a1=5a_{1}=5 and calculate a2a_{2}. \newlinea2=3a11=3×51=151=14a_{2} = 3a_{1} - 1 = 3\times5 - 1 = 15 - 1 = 14. \newlineThis matches the second term of the given sequence, but we need to check the third term as well.
  7. Check Formula 44: Using the formula a1=5a_{1}=5 and an=3an11a_{n}=3a_{n-1}-1, let's calculate a3a_{3}. a3=3a21=3×141=421=41a_{3} = 3a_{2} - 1 = 3\times14 - 1 = 42 - 1 = 41. This does not match the third term of the given sequence, which is 3232. Therefore, this recursive formula does not produce the given sequence.

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