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Which of these strategies would eliminate a variable in the system of equations?

{[6x+5y=1],[6x-5y=7]:}
Choose 2 answers:
A Multiply the top equation by 7 , then subtract the bottom equation from the top equation.
B Subtract the bottom equation from the top equation.
C.
Add the equations.

Which of these strategies would eliminate a variable in the system of equations?\newline{6x+5y=1 6x5y=7\begin{cases} 6x+5y=1 \ 6x-5y=7 \end{cases}\newlineChoose 22 answers:\newlineA Multiply the top equation by 77, then subtract the bottom equation from the top equation.\newlineB Subtract the bottom equation from the top equation.\newlineC. Add the equations.

Full solution

Q. Which of these strategies would eliminate a variable in the system of equations?\newline{6x+5y=1 6x5y=7\begin{cases} 6x+5y=1 \ 6x-5y=7 \end{cases}\newlineChoose 22 answers:\newlineA Multiply the top equation by 77, then subtract the bottom equation from the top equation.\newlineB Subtract the bottom equation from the top equation.\newlineC. Add the equations.
  1. Analyze Equations: Analyze the system of equations to determine which strategies could eliminate a variable.\newlineWe have the system of equations:\newline6x+5y=16x + 5y = 1\newline6x5y=76x - 5y = 7\newlineTo eliminate a variable, we can either add or subtract the equations so that one of the variables cancels out.
  2. Strategy A: Evaluate Strategy A - Multiply the top equation by 77, then subtract the bottom equation from the top equation.\newlineIf we multiply the top equation by 77, we get:\newline(6x+5y)×7=1×7(6x + 5y) \times 7 = 1 \times 7\newline42x+35y=742x + 35y = 7\newlineNow, if we subtract the bottom equation from this new equation:\newline(42x+35y)(6x5y)=77(42x + 35y) - (6x - 5y) = 7 - 7\newlineThis would result in:\newline42x+35y6x+5y=042x + 35y - 6x + 5y = 0\newline36x+40y=036x + 40y = 0\newlineThis does not eliminate any variable.
  3. Strategy B: Evaluate Strategy B - Subtract the bottom equation from the top equation.\newlineIf we subtract the bottom equation from the top equation, we get:\newline(6x+5y)(6x5y)=17(6x + 5y) - (6x - 5y) = 1 - 7\newlineThis simplifies to:\newline6x+5y6x+5y=66x + 5y - 6x + 5y = -6\newline10y=610y = -6\newlineThis strategy eliminates the variable xx.
  4. Strategy C: Evaluate Strategy C - Add the equations.\newlineIf we add the two equations, we get:\newline(6x+5y)+(6x5y)=1+7(6x + 5y) + (6x - 5y) = 1 + 7\newlineThis simplifies to:\newline12x=812x = 8\newlineThis strategy eliminates the variable yy.

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