Which of these points are sqrt 45 units away from (-3,1)? Select all that apply. Multi-select Choices: (A)(-9,4) (B)(-6,-5) (C)(0,7) (D)(3,-2)

Calculate sqrt 45: Calculate sqrt 45 to find the distance we need. sqrt 45 ≈ 6.708 (using a calculator).Check point A: Check each point to see if it's sqrt 45 units away from (-3,1). Start with point A (-9,4). Distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2) Distance from (-3,1) to (-9,4) = sqrt((-9 + 3)^2 + (4 - 1)^2) = sqrt((-6)^2 + 3^2) = sqrt(36 + 9) = sqrt(45) = 6.708.Check point B: Check point B (-6,-5). Distance from (-3,1) to (-6,-5) = sqrt((-6 + 3)^2 + (-5 - 1)^2) = sqrt((-3)^2 + (-6)^2) = sqrt(9 + 36) = sqrt(45) = 6.708.Check point C: Check point C (0,7). Distance from (-3,1) to (0,7) = sqrt((0 + 3)^2 + (7 - 1)^2) = sqrt(3^2 + 6^2) = sqrt(9 + 36) = sqrt(45) = 6.708.Check point D: Check point D (3,-2). Distance from (-3,1) to (3,-2) = sqrt((3 + 3)^2 + (-2 - 1)^2) = sqrt(6^2 + (-3)^2) = sqrt(36 + 9) = sqrt(45) = 6.708.

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Math Problems

Grade 8

Estimate positive and negative square roots

Full solution

Q. Which of these points are

\sqrt{45}

units away from

(-3,1)

? Select all that apply.

\newline

Multi-select Choices:

\newline

(A)

(-9,4)

\newline

(B)

(-6,-5)

\newline

(C)

(0,7)

\newline

(D)

(3,-2)

Calculate $\sqrt{45}$ : Calculate $\sqrt{45}$ to find the distance we need. $\newline$ $\sqrt{45} \approx 6.708$ (using a calculator).
Check point A: Check each point to see if it's $\sqrt{45}$ units away from $(-3,1)$ . Start with point A $(-9,4)$ . Distance formula: $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ Distance from $(-3,1)$ to $(-9,4)$ = $\sqrt{(-9 + 3)^2 + (4 - 1)^2}$ = $\sqrt{(-6)^2 + 3^2}$ = $\sqrt{36 + 9}$ = $\sqrt{45}$ = $(-3,1)$ $0$ .
Check point B: Check point B $(-6,-5)$ . $\newline$ Distance from $(-3,1)$ to $(-6,-5)$ = $\sqrt{(-6 + 3)^2 + (-5 - 1)^2} = \sqrt{(-3)^2 + (-6)^2} = \sqrt{9 + 36} = \sqrt{45} = 6.708$ .
Check point C: Check point C $(0,7)$ . $\newline$ Distance from $(-3,1)$ to $(0,7)$ = $\sqrt{(0 + 3)^2 + (7 - 1)^2}$ = $\sqrt{3^2 + 6^2}$ = $\sqrt{9 + 36}$ = $\sqrt{45}$ = $6.708$ .
Check point D: Check point D $(3,-2)$ . $\newline$ Distance from $(-3,1)$ to $(3,-2)$ = $\sqrt{(3 + 3)^2 + (-2 - 1)^2}$ = $\sqrt{6^2 + (-3)^2}$ = $\sqrt{36 + 9}$ = $\sqrt{45}$ = $6.708$ .