Which of the following values are solutions to the inequality -10+3x <= 10 ? I. 12 II. 3 III. 9 None I only II only III only I and II I and III II and III I, II and III

Solve for x: Solve the inequality for x. Start with the inequality -10 + 3x <= 10. Add 10 to both sides to isolate the term with x. -10 + 3x + 10 <= 10 + 10 3x <= 20 Now, divide both sides by 3 to solve for x. 3x / 3 <= 20 / 3 x <= 20 / 3 x <= 6.666...Add 10 and isolate x: Test each value to see if it satisfies the inequality x <= 6.666... I. Test if x = 12 is a solution. 12 <= 6.666... (This is false, so 12 is not a solution.)Divide by 3: Test the second value. II. Test if x = 3 is a solution. 3 <= 6.666... (This is true, so 3 is a solution.)Test x=12: Test the third value. III. Test if x = 9 is a solution. 9 <= 6.666... (This is false, so 9 is not a solution.)Test x=3: Combine the results from steps 2, 3, and 4 to determine which of the given choices are correct. From the tests, we found that: I. 12 is not a solution. II. 3 is a solution. III. 9 is not a solution. Therefore, the correct choice is ＂II only.＂

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Which of the following values are solutions to the inequality
-10+3x <= 10 ?
I. 12
II. 3
III. 9
None
I only
II only
III only
I and II
I and III
II and III
I, II and III

Which of the following values are solutions to the inequality $-10+3 x \leq 10$ ? $\newline$ I. $12$ $\newline$ II. $3$ $\newline$ III. $9$ $\newline$ None $\newline$ I only $\newline$ II only $\newline$ III only $\newline$ I and II $\newline$ I and III $\newline$ II and III $\newline$ I, II and III

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Math Problems

Grade 8

Solutions to inequalities

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Q. Which of the following values are solutions to the inequality

-10+3 x \leq 10

\newline

12

\newline

II.

3

\newline

III.

9

\newline

None

\newline

I only

\newline

II only

\newline

III only

\newline

I and II

\newline

I and III

\newline

II and III

\newline

I, II and III

Solve for x: Solve the inequality for x. $\newline$ Start with the inequality $-10 + 3x \leq 10$ . $\newline$ Add $10$ to both sides to isolate the term with x. $\newline$ $-10 + 3x + 10 \leq 10 + 10$ $\newline$ $3x \leq 20$ $\newline$ Now, divide both sides by $3$ to solve for x. $\newline$ $\frac{3x}{3} \leq \frac{20}{3}$ $\newline$ $x \leq \frac{20}{3}$ $\newline$ $x \leq 6.666\ldots$
Add $10$ and isolate $x$ : Test each value to see if it satisfies the inequality $x \leq 6.666...$ $\newline$ I. Test if $x = 12$ is a solution. $\newline$ $12 \leq 6.666...$ (This is false, so $12$ is not a solution.)
Divide by $3$ : Test the second value. $\newline$ II. Test if $x = 3$ is a solution. $\newline$ $3 \leq 6.666\ldots$ (This is true, so $3$ is a solution.)
Test $x=12$ : Test the third value. $\newline$ III. Test if $x = 9$ is a solution. $\newline$ $9 \leq 6.666\ldots$ (This is false, so $9$ is not a solution.)
Test $x=3$ : Combine the results from steps $2$ , $3$ , and $4$ to determine which of the given choices are correct. $\newline$ From the tests, we found that: $\newline$ I. $12$ is not a solution. $\newline$ II. $3$ is a solution. $\newline$ III. $9$ is not a solution. $\newline$ Therefore, the correct choice is ＂II only.＂