Which of the following values are solutions to the inequality 6x-3 >= 8 ? I. 10 II. -5 III. -2 None I only II only III only I and II I and III II and III I, II and III

Isolate x by adding: Solve the inequality 6x - 3 >= 8 for x. First, add 3 to both sides of the inequality to isolate the term with x on one side. 6x - 3 + 3 >= 8 + 3 This simplifies to: 6x >= 11Divide by 6: Now, divide both sides of the inequality by 6 to solve for x. 6x / 6 >= 11 / 6 This simplifies to: x >= 11/6Check value I: Check if the value I (10) is a solution to the inequality x >= 11/6. Substitute x = 10 into the inequality: 10 >= 11/6 Since 10 is greater than 11/6, value I (10) is a solution to the inequality.Check value II: Check if the value II (-5) is a solution to the inequality x >= 11/6. Substitute x = -5 into the inequality: -5 >= 11/6 Since -5 is not greater than 11/6, value II (-5) is not a solution to the inequality.Check value III: Check if the value III (-2) is a solution to the inequality x >= 11/6. Substitute x = -2 into the inequality: -2 >= 11/6 Since -2 is not greater than 11/6, value III (-2) is not a solution to the inequality.

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Which of the following values are solutions to the inequality
6x-3 >= 8 ?
I. 10
II. -5
III. -2
None
I only
II only
III only
I and II
I and III
II and III
I, II and III

Which of the following values are solutions to the inequality $6 x-3 \geq 8$ ? $\newline$ I. $10$ $\newline$ II. $-5$ $\newline$ III. $-2$ $\newline$ None $\newline$ I only $\newline$ II only $\newline$ III only $\newline$ I and II $\newline$ I and III $\newline$ II and III $\newline$ I, II and III

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Algebra 1

Does (x, y) satisfy the inequality?

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Q. Which of the following values are solutions to the inequality

6 x-3 \geq 8

\newline

10

\newline

II.

-5

\newline

III.

-2

\newline

None

\newline

I only

\newline

II only

\newline

III only

\newline

I and II

\newline

I and III

\newline

II and III

\newline

I, II and III

Isolate x by adding: Solve the inequality $6x - 3 \geq 8$ for $x$ . $\newline$ First, add $3$ to both sides of the inequality to isolate the term with $x$ on one side. $\newline$ $6x - 3 + 3 \geq 8 + 3$ $\newline$ This simplifies to: $\newline$ $6x \geq 11$
Divide by $6$ : Now, divide both sides of the inequality by $6$ to solve for $x$ . $\frac{6x}{6} \geq \frac{11}{6}$ This simplifies to: $x \geq \frac{11}{6}$
Check value I: Check if the value I ( $10$ ) is a solution to the inequality $x \geq \frac{11}{6}$ . $\newline$ Substitute $x = 10$ into the inequality: $\newline$ $10 \geq \frac{11}{6}$ $\newline$ Since $10$ is greater than $\frac{11}{6}$ , value I ( $10$ ) is a solution to the inequality.
Check value II: Check if the value II ( $-5$ ) is a solution to the inequality $x \geq \frac{11}{6}$ . Substitute $x = -5$ into the inequality: $-5 \geq \frac{11}{6}$ Since $-5$ is not greater than $\frac{11}{6}$ , value II ( $-5$ ) is not a solution to the inequality.
Check value III: Check if the value III ( $-2$ ) is a solution to the inequality $x \geq \frac{11}{6}$ . Substitute $x = -2$ into the inequality: $-2 \geq \frac{11}{6}$ Since $-2$ is not greater than $\frac{11}{6}$ , value III ( $-2$ ) is not a solution to the inequality.