Jack is fixing up his home and must spend less than $4,800 to hire carpenters and painters. Carpenters charge $60 per hour and painters charge $32 per hour. Select the inequality in standard form that describes this situation. Use the given numbers and the following variables.x= the number of hours of carpentryy= the number of hours of paintingChoices:(A) 32x + 60y < 4,800(B) 60x + 32y < 4,800 (C) 32x - 60y < 4,800 (D) 60x - 32y < 4,800
Q. Jack is fixing up his home and must spend less than $4,800 to hire carpenters and painters. Carpenters charge $60 per hour and painters charge $32 per hour. Select the inequality in standard form that describes this situation. Use the given numbers and the following variables.x= the number of hours of carpentryy= the number of hours of paintingChoices:(A) 32x+60y<4,800(B) 60x+32y<4,800(C) 32x−60y<4,800(D) 60x−32y<4,800
Identify Cost per Hour: Identify the cost per hour for carpenters and the variable that represents their hours worked. Carpenters charge $60 per hour, and the number of hours of carpentry is represented by x. Therefore, the total cost for carpenters is 60x.
Identify Painter Cost: Identify the cost per hour for painters and the variable that represents their hours worked. Painters charge $32 per hour, and the number of hours of painting is represented by y. Therefore, the total cost for painters is 32y.
Combine Total Costs: Combine the costs for carpenters and painters to represent the total cost of hiring both. The total cost is the sum of the cost for carpenters and the cost for painters, which is 60x+32y.
Set Cost Limit: Since Jack must spend less than \$\(4\),\(800\), we set the total cost of hiring carpenters and painters to be less than \$\(4\),\(800\). This gives us the inequality \(60x + 32y < 4,800\).
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