Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Which of the following equations represents a line that passes through the points 
(0,7) and 
(-9,10) ?
I. 
2x+6y=42
II. 
y=-(1)/(3)x+7
Neither
I only
II only
I and II

Which of the following equations represents a line that passes through the points (0,7) (0,7) and (9,10) (-9,10) ?\newlineI. 2x+6y=42 2 x+6 y=42 \newlineII. y=13x+7 y=-\frac{1}{3} x+7 \newlineNeither\newlineI only\newlineII only\newlineI and II

Full solution

Q. Which of the following equations represents a line that passes through the points (0,7) (0,7) and (9,10) (-9,10) ?\newlineI. 2x+6y=42 2 x+6 y=42 \newlineII. y=13x+7 y=-\frac{1}{3} x+7 \newlineNeither\newlineI only\newlineII only\newlineI and II
  1. Calculate Slope: First, we need to determine the slope of the line that passes through the points (0,7)(0,7) and (9,10)(-9,10). The slope (m)(m) is calculated using the formula m=(y2y1)(x2x1)m = \frac{(y_2 - y_1)}{(x_2 - x_1)}.
  2. Find Y-Intercept: Using the points (0,7)(0,7) as (x1,y1)(x_1,y_1) and (9,10)(-9,10) as (x2,y2)(x_2,y_2), we calculate the slope as follows:\newlinem=10790=39=13.m = \frac{10 - 7}{-9 - 0} = \frac{3}{-9} = -\frac{1}{3}.
  3. Write Equation: Now that we have the slope, we can use one of the points to find the y-intercept bb of the line. We can use the point (0,7)(0,7) because it gives us the y-intercept directly since the x-coordinate is 00. Therefore, b=7b = 7.
  4. Check Equation I: With the slope m=13m = -\frac{1}{3} and y-intercept b=7b = 7, the equation of the line in slope-intercept form is y=mx+by = mx + b, which gives us y=13x+7y = -\frac{1}{3}x + 7.
  5. Check Equation II: Now let's check if equation I, 2x+6y=422x + 6y = 42, represents the line. To do this, we can rearrange the equation into slope-intercept form (y=mx+by = mx + b) by solving for y:\newline6y=2x+426y = -2x + 42\newliney=13x+7y = -\frac{1}{3}x + 7.
  6. Check Equation II: Now let's check if equation I, 2x+6y=422x + 6y = 42, represents the line. To do this, we can rearrange the equation into slope-intercept form (y=mx+b)(y = mx + b) by solving for yy:\newline6y=2x+426y = -2x + 42\newliney=13x+7y = -\frac{1}{3}x + 7.We see that equation I, when simplified, matches the equation y=13x+7y = -\frac{1}{3}x + 7, which we derived from the points. Therefore, equation I represents the line that passes through the points (0,7)(0,7) and (9,10)(-9,10).
  7. Check Equation II: Now let's check if equation I, 2x+6y=422x + 6y = 42, represents the line. To do this, we can rearrange the equation into slope-intercept form (y=mx+b)(y = mx + b) by solving for yy: \newline6y=2x+426y = -2x + 42\newliney=13x+7y = -\frac{1}{3}x + 7. We see that equation I, when simplified, matches the equation y=13x+7y = -\frac{1}{3}x + 7, which we derived from the points. Therefore, equation I represents the line that passes through the points (0,7)(0,7) and (9,10)(-9,10).Next, we check equation II, y=13x+7y = -\frac{1}{3}x + 7, which is already in slope-intercept form. This equation matches the one we derived from the points, so equation II also represents the line that passes through the points (0,7)(0,7) and (9,10)(-9,10).

More problems from Write a linear equation from two points