Which function would be produced by a horizontal stretch of the graph of y=sqrtx followed by a reflection in the x-axis? y=sqrt(2(-x))quad y=-sqrt(2x)quad y=sqrt((1)/(2)(-x))quad y=-sqrt((1)/(2)x) My Progress Type here to search

Horizontal Stretch Effect: Understand the effect of a horizontal stretch on y = sqrt(x). A horizontal stretch by a factor of 2 would replace x with (1/2)x in the function, resulting in y = sqrt((1/2)x). Reflection in x-axis: Apply the reflection in the x-axis to the stretched function. Reflecting y = sqrt((1/2)x) in the x-axis changes y to -y, so the new function becomes y = -sqrt((1/2)x).

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Which function would be produced by a horizontal stretch of the graph of $\newline$ $y=\sqrt{x}$ followed by a reflection in the $x$ -axis? $\newline$ a) $y=\sqrt{2(-x)}$ $\newline$ b) $y=-\sqrt{2x}$ $\newline$ c) $y=\sqrt{\left(\frac{1}{2}\right)(-x)}$ $\newline$ d) $y=-\sqrt{\left(\frac{1}{2}\right)x}$

View step-by-step help

Home

Math Problems

Algebra 2

Dilations of functions

Full solution

Q. Which function would be produced by a horizontal stretch of the graph of

\newline

y=\sqrt{x}

followed by a reflection in the

x

-axis?

\newline

y=\sqrt{2(-x)}

\newline

y=-\sqrt{2x}

\newline

y=\sqrt{\left(\frac{1}{2}\right)(-x)}

\newline

y=-\sqrt{\left(\frac{1}{2}\right)x}

Horizontal Stretch Effect: Understand the effect of a horizontal stretch on $y = \sqrt{x}$ . A horizontal stretch by a factor of $2$ would replace $x$ with $(1/2)x$ in the function, resulting in $y = \sqrt{(1/2)x}$ .
Reflection in x-axis: Apply the reflection in the x-axis to the stretched function. Reflecting $y = \sqrt{\left(\frac{1}{2}\right)x}$ in the x-axis changes $y$ to $-y$ , so the new function becomes $y = -\sqrt{\left(\frac{1}{2}\right)x}$ .