Q. Which equation has the same solution as x2+x+19=−2 ?(x+0.5)2=−21.25(x−0.5)2=−21.25(x−0.5)2=−20.75(x+0.5)2=−20.75
Simplify Equation: Simplify the given equation by moving all terms to one side to set the equation to zero.x2+x+19=−2 can be rewritten as x2+x+21=0 by adding 2 to both sides.
Identify a, b, c: Compare the given equation x2+x+21=0 with the standard form of a quadratic equationax2+bx+c=0 to identify a, b, and c. Here, a=1, b=1, and b0.
Compare with Choices: Look at the provided answer choices to determine which one can be rewritten in the form of x2+x+21=0. We need to expand each choice and compare it with the given equation.
Expand Choice 1: Expand the first choice (x+0.5)2=−21.25.(x + 0.5)^2 = x^2 + 2\times(0.5)\times x + (0.5)^2 = x^2 + x + 0.25\.This does not match the given equation \$x^2 + x + 21 = 0.
Expand Choice 2: Expand the second choice (x−0.5)2=−21.25.(x - 0.5)^2 = x^2 - 2\times(0.5)\times x + (0.5)^2 = x^2 - x + 0.25\.This does not match the given equation \$x^2 + x + 21 = 0.
Expand Choice 3: Expand the third choice (x−0.5)2=−20.75.(x - 0.5)^2 = x^2 - 2\times(0.5)\times x + (0.5)^2 = x^2 - x + 0.25\.This does not match the given equation \$x^2 + x + 21 = 0.
Expand Choice 4: Expand the fourth choice (x+0.5)2=−20.75.(x+0.5)2=x2+2×(0.5)×x+(0.5)2=x2+x+0.25. Now, we need to move −20.75 to the other side to compare it with the given equation.x2+x+0.25=20.75x2+x+21=0 (by adding 20.75 to both sides) This matches the given equation x2+x+21=0.