Q. When an integer is subtracted from 8 times the next consecutive integer, the difference is −13 . Find the value of the greater integer.Answer:
Define Integers: Let's denote the first integer as x. The next consecutive integer is x+1. According to the problem, 8 times the next consecutive integer minus the first integer equals −13. We can write this as an equation:8(x+1)−x=−13
Distribute 8: Now, let's distribute the 8 to both terms inside the parentheses: 8x+8−x=−13
Combine Like Terms: Combine like terms by subtracting x from 8x: 7x+8=−13
Isolate Variable x: Next, we need to isolate the variable x. To do this, we subtract 8 from both sides of the equation:7x=−13−8
Calculate Right Side: Now, calculate the right side of the equation: 7x=−21
Divide by 7: To find the value of x, divide both sides of the equation by 7:x=7−21
Calculate x: Calculate the division to find the value of x:x=−3
Find Greater Integer: Since x is the first integer, the next consecutive integer, which is the greater integer, is x+1. So we need to add 1 to our value of x to find the greater integer:Greater integer = x+1=−3+1
Calculate Greater Integer: Calculate the sum to find the value of the greater integer: Greater integer = −2