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When an integer is subtracted from 8 times the next consecutive integer, the difference is -13 . Find the value of the greater integer.
Answer:

When an integer is subtracted from 88 times the next consecutive integer, the difference is 13-13 . Find the value of the greater integer.\newlineAnswer:

Full solution

Q. When an integer is subtracted from 88 times the next consecutive integer, the difference is 13-13 . Find the value of the greater integer.\newlineAnswer:
  1. Define Integers: Let's denote the first integer as xx. The next consecutive integer is x+1x + 1. According to the problem, 88 times the next consecutive integer minus the first integer equals 13-13. We can write this as an equation:\newline8(x+1)x=138(x + 1) - x = -13
  2. Distribute 88: Now, let's distribute the 88 to both terms inside the parentheses: 8x+8x=138x + 8 - x = -13
  3. Combine Like Terms: Combine like terms by subtracting xx from 8x8x: 7x+8=137x + 8 = -13
  4. Isolate Variable xx: Next, we need to isolate the variable xx. To do this, we subtract 88 from both sides of the equation:\newline7x=1387x = -13 - 8
  5. Calculate Right Side: Now, calculate the right side of the equation: 7x=217x = -21
  6. Divide by 77: To find the value of xx, divide both sides of the equation by 77:\newlinex=217x = \frac{-21}{7}
  7. Calculate xx: Calculate the division to find the value of xx:x=3x = -3
  8. Find Greater Integer: Since xx is the first integer, the next consecutive integer, which is the greater integer, is x+1x + 1. So we need to add 11 to our value of xx to find the greater integer:\newlineGreater integer = x+1=3+1x + 1 = -3 + 1
  9. Calculate Greater Integer: Calculate the sum to find the value of the greater integer: Greater integer = 2-2

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