What value of w is a solution to this equation? 16 + w = 28 Choices: (A)w = 11 (B)w = 12

Isolate w in the equation: Step 1: Start by isolating w in the equation. 16 + w = 28 Subtract 16 from both sides to isolate w, 16 + w - 16 = 28 - 16 w = 12 Check solution by substitution: Step 2: Check the solution by substituting w back into the original equation. 16 + 12 = 28 This confirms that w = 12 is correct.

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What value of $w$ is a solution to this equation? $\newline$ $16 + w = 28$ $\newline$ Choices: $\newline$ (A) $w = 11$ $\newline$ (B) $w = 12$

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Math Problems

Grade 6

Which x satisfies an equation?

Full solution

Q. What value of

w

is a solution to this equation?

\newline

16 + w = 28

\newline

Choices:

\newline

(A)

w = 11

\newline

(B)

w = 12

Isolate $w$ in the equation: Step $1$ : Start by isolating $w$ in the equation. $16 + w = 28$ Subtract $16$ from both sides to isolate $w$ , $16 + w - 16 = 28 - 16$ $w = 12$
Check solution by substitution: Step $2$ : Check the solution by substituting $w$ back into the original equation. $16 + 12 = 28$ This confirms that $w = 12$ is correct.