What term should go in the box to make the statement true? 3x^2+10x−8=(3x−2)(x+⬚)

Expand Factors: To find the missing term in the box, we need to expand the right side of the equation and compare it to the left side. Let's start by expanding the known factors without the box term. (3x - 2)(x) = 3x^2 - 2xFind Middle Term: Now, we need to find a term that, when multiplied by 3x, gives us the middle term of the left side of the equation, which is 10x. We already have -2x from the expansion, so we need to find a number that will result in (3x * number) + (-2x) = 10x.Calculate Value of 'a': Let's denote the number we are looking for as 'a'. So we have: 3x * a - 2x = 10x 3ax = 10x + 2x 3ax = 12x a = 12x / 3x a = 4Complete the Expression: Now that we have found the value of 'a', we can complete the expression: (3x - 2)(x + 4)

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Q. What term should go in the box to make the statement true?

\newline

3x^2+10x-8=(3x-2)(x

\square)

Expand Factors: To find the missing term in the box, we need to expand the right side of the equation and compare it to the left side. Let's start by expanding the known factors without the box term. $\newline$ $(3x - 2)(x) = 3x^2 - 2x$
Find Middle Term: Now, we need to find a term that, when multiplied by $3x$ , gives us the middle term of the left side of the equation, which is $10x$ . We already have $-2x$ from the expansion, so we need to find a number that will result in $(3x \times \text{number}) + (-2x) = 10x$ .
Calculate Value of 'a': Let's denote the number we are looking for as 'a'. So we have: $\newline$ $3x \cdot a - 2x = 10x$ $\newline$ $3ax = 10x + 2x$ $\newline$ $3ax = 12x$ $\newline$ $a = \frac{12x}{3x}$ $\newline$ $a = 4$
Complete the Expression: Now that we have found the value of $a$ , we can complete the expression: $(3x - 2)(x + 4)$