What is the x-intercept of the graph of y=(x-5)^(2) ? Choose 1 answer: (A) -25 (B) -5 (C) 5 (D) 25

Set y equal to 0: To find the x-intercept of the graph, we need to set y equal to 0 and solve for x. So, we set the equation y = (x - 5)² to 0: 0 = (x - 5)²Find x value: Now, we need to find the value of x that makes the equation true. Since we have a square, we can take the square root of both sides to solve for x. √0 = √(x - 5)²Take square root: Taking the square root of both sides gives us: 0 = x - 5Isolate x: To isolate x, we add 5 to both sides of the equation: 0 + 5 = x - 5 + 5Simplify equation: This simplifies to: 5 = x

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What is the $x$ -intercept of the graph of $y=(x-5)^{2}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $-25$ $\newline$ (B) $-5$ $\newline$ (C) $5$ $\newline$ (D) $25$

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Algebra 2

Transformations of functions

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Q. What is the

x

-intercept of the graph of

y=(x-5)^{2}

\newline

Choose

1

answer:

\newline

(A)

-25

\newline

(B)

-5

\newline

(C)

5

\newline

(D)

25

Set $y$ equal to $0$ : To find the x-intercept of the graph, we need to set $y$ equal to $0$ and solve for $x$ . So, we set the equation $y = (x - 5)^2$ to $0$ : $0 = (x - 5)^2$
Find x value: Now, we need to find the value of $x$ that makes the equation true. Since we have a square, we can take the square root of both sides to solve for $x$ . $\sqrt{0} = \sqrt{(x - 5)^2}$
Take square root: Taking the square root of both sides gives us: $\newline$ $0 = x - 5$
Isolate x: To isolate x, we add $5$ to both sides of the equation: $\newline$ $0 + 5 = x - 5 + 5$
Simplify equation: This simplifies to: $5 = x$