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What is the value of 
log_(8)root(4)(512) ?
Answer:

Evaluate.\newlinelog85124\log _{8} \sqrt[4]{512}\newlineWrite your answer in simplest form.

Full solution

Q. Evaluate.\newlinelog85124\log _{8} \sqrt[4]{512}\newlineWrite your answer in simplest form.
  1. Identify Fourth Root of 512512: Identify the value of the fourth root of 512512.\newlineThe fourth root of 512512 is the number that, when raised to the power of 44, equals 512512. We can calculate this as 512(1/4)512^{(1/4)}.\newline512=29512 = 2^9, so 512(1/4)=(29)(1/4)=2(9/4)=22.25=22×20.25=4×20.25512^{(1/4)} = (2^9)^{(1/4)} = 2^{(9/4)} = 2^{2.25} = 2^2 \times 2^{0.25} = 4 \times 2^{0.25}.\newlineSince 20.252^{0.25} is the fourth root of 22, and the fourth root of 22 is 21/4=1.1892072^{1/4} = 1.189207 (approximately), we have 4×1.189207=4.7568284 \times 1.189207 = 4.756828 (approximately).\newlineHowever, we know that 222^2 is exactly 44, so the fourth root of 512512 is exactly 22=42^2 = 4.
  2. Apply Logarithm: Apply the logarithm to the fourth root of 512512. We need to find extlog8(4) ext{log}_8(4), which we can write as extlog8(4) ext{log}_{8}(4).
  3. Convert Base to 22: Convert the base of the logarithm from 88 to 22. Since 88 is 232^3, we can use the change of base formula to convert the base from 88 to 22. The change of base formula is logb(a)=logc(a)logc(b)\log_b(a) = \frac{\log_c(a)}{\log_c(b)}. So, log8(4)=log2(4)log2(8)\log_{8}(4) = \frac{\log_{2}(4)}{\log_{2}(8)}.
  4. Calculate Log Values: Calculate log24\log_{2} 4 and log28\log_{2} 8. We know that 44 is 222^{2}, so log2(4)=2\log_{2}(4) = 2. We also know that 88 is 232^{3}, so log2(8)=3\log_{2}(8) = 3.
  5. Divide Logarithms: Divide the two logarithms to find the value.\newlineNow we divide the results from Step 44 to find the value of log8(4)\log_{8}(4).\newlinelog8(4)=log2(4)log2(8)=23.\log_{8}(4) = \frac{\log_{2}(4)}{\log_{2}(8)} = \frac{2}{3}.

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