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What is the value of 
A when we rewrite 
4^(x+3)-4^(x) as 
A*4^(x) ?

A=

What is the value of A A when we rewrite 4x+34x 4^{x+3}-4^{x} as A4x A \cdot 4^{x} ?\newlineA= A=

Full solution

Q. What is the value of A A when we rewrite 4x+34x 4^{x+3}-4^{x} as A4x A \cdot 4^{x} ?\newlineA= A=
  1. Recognize Property of Exponents: We need to factor out 4x4^{x} from the expression 4x+34x4^{x+3} - 4^{x}. To do this, we recognize that 4x+34^{x+3} can be written as 4x434^{x}\cdot4^{3} because of the property of exponents that states am+n=amana^{m+n} = a^{m}\cdot a^{n}.
  2. Rewrite Using Property: Now we rewrite the expression using this property: 4(x+3)4x=4x434x4^{(x+3)} - 4^{x} = 4^{x}\cdot4^{3} - 4^{x}. We can factor 4x4^{x} out of both terms to get 4x(431)4^{x} \cdot (4^{3} - 1).
  3. Calculate Result: We calculate 4314^{3} - 1. Since 434^{3} is 4×4×44\times4\times4, which equals 6464, we have 641=6364 - 1 = 63.
  4. Substitute Result: Now we substitute this result back into the factored expression: 4x×(431)4^{x} \times (4^{3} - 1) becomes 4x×634^{x} \times 63.
  5. Identify Value of A: We can see that the expression 4x×634^{x} \times 63 is in the form of A×4xA\times4^{x}, which means AA is equal to 6363.

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