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What is the solution to this system of equations?

{[x+3y-z=6],[4x-2y+2z=-10],[6x+z=-12]:}

What is the solution to this system of equations?\newline{x+3yz=64x2y+2z=106x+z=12 \left\{\begin{array}{c} x+3 y-z=6 \\ 4 x-2 y+2 z=-10 \\ 6 x+z=-12 \end{array}\right.

Full solution

Q. What is the solution to this system of equations?\newline{x+3yz=64x2y+2z=106x+z=12 \left\{\begin{array}{c} x+3 y-z=6 \\ 4 x-2 y+2 z=-10 \\ 6 x+z=-12 \end{array}\right.
  1. Write Equations: Write down the system of equations to be solved. \left\{\begin{array}{l}x+3y-z=6,\4x-2y+2z=-10,\6x+z=-12:\end{array}\right. We need to find the values of xx, yy, and zz that satisfy all three equations simultaneously.
  2. Eliminate Variable zz: Choose two equations to eliminate one variable. We can start by eliminating zz using the first and third equations.\newlineFirst equation: x+3yz=6x + 3y - z = 6\newlineThird equation: 6x+z=126x + z = -12\newlineAdd the first and third equations to eliminate zz:\newline(x+3yz)+(6x+z)=612(x + 3y - z) + (6x + z) = 6 - 12\newline7x+3y=67x + 3y = -6
  3. Eliminate Variable zz: Now, we need to eliminate the same variable, zz, using the second and third equations.\newlineSecond equation: 4x2y+2z=104x - 2y + 2z = -10\newlineThird equation: 6x+z=126x + z = -12\newlineTo eliminate zz, we can multiply the third equation by 22 and then add it to the second equation:\newline(4x2y+2z)+2(6x+z)=10+2(12)(4x - 2y + 2z) + 2*(6x + z) = -10 + 2*(-12)\newline4x2y+2z+12x+2z=10244x - 2y + 2z + 12x + 2z = -10 - 24\newline16x2y+4z=3416x - 2y + 4z = -34\newlineNow, we divide the entire equation by 22 to simplify:\newlinezz00\newlinezz11
  4. Two-Variable Equations: We now have two equations with two variables xx and yy:7x+3y=67x + 3y = -68xy=178x - y = -17We can multiply the second equation by 33 to align the yy terms:3(8xy)=3(17)3*(8x - y) = 3*(-17)24x3y=5124x - 3y = -51Now we can add this result to the first equation to eliminate yy:(7x+3y)+(24x3y)=6+(51)(7x + 3y) + (24x - 3y) = -6 + (-51)31x=5731x = -57Divide both sides by 3131 to solve for xx:x=57/31x = -57 / 31x=1.8387x = -1.8387 (rounded to four decimal places)
  5. Solve for x: Substitute the value of xx into one of the two-variable equations to solve for yy. We can use the equation 8xy=178x - y = -17:8(1.8387)y=178(-1.8387) - y = -1714.7096y=17-14.7096 - y = -17Add 14.709614.7096 to both sides to solve for yy:y=17+14.7096-y = -17 + 14.7096y=2.2904-y = -2.2904Multiply both sides by 1-1:yy00 (rounded to four decimal places)
  6. Solve for y: Substitute the values of xx and yy into one of the original equations to solve for zz. We can use the first equation x+3yz=6x + 3y - z = 6: \newline1.8387+3(2.2904)z=6-1.8387 + 3(2.2904) - z = 6\newline1.8387+6.8712z=6-1.8387 + 6.8712 - z = 6\newline4.0325z=64.0325 - z = 6\newlineSubtract 4.03254.0325 from both sides to solve for zz:\newlinez=64.0325-z = 6 - 4.0325\newlinez=1.9675-z = 1.9675\newlineMultiply both sides by 1-1:\newlinez=1.9675z = -1.9675 (rounded to four decimal places)