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What is the solution to the compound inequality in inteval notation?

2(x+3) > 6" or "2x+3 <= -7

What is the solution to the compound inequality in inteval notation?\newline 2(x+3)>6 \text { or } 2 x+3 \leq-7

Full solution

Q. What is the solution to the compound inequality in inteval notation?\newline2(x+3)>6 or 2x+37 2(x+3)>6 \text { or } 2 x+3 \leq-7
  1. Distribute and Simplify: Solve the first inequality 2(x+3) > 6. First, distribute the 22 to both terms inside the parentheses: 2\times x + 2\times 3 > 6, which simplifies to 2x + 6 > 6.
  2. Subtract to Isolate Variable: Subtract 66 from both sides of the inequality 2x + 6 > 6 to isolate the term with the variable: 2x + 6 - 6 > 6 - 6, which simplifies to 2x > 0.
  3. Divide to Solve for x: Divide both sides of the inequality 2x > 0 by 22 to solve for xx: \frac{2x}{2} > \frac{0}{2}, which simplifies to x > 0.
  4. Subtract to Isolate Variable: Solve the second inequality 2x+372x + 3 \leq -7. Subtract 33 from both sides of the inequality to isolate the term with the variable: 2x+33732x + 3 - 3 \leq -7 - 3, which simplifies to 2x102x \leq -10.
  5. Divide to Solve for xx: Divide both sides of the inequality 2x102x \leq -10 by 22 to solve for xx: 2x2102\frac{2x}{2} \leq \frac{-10}{2}, which simplifies to x5x \leq -5.
  6. Combine Solutions: Combine the solutions of the two inequalities to express the solution of the compound inequality.\newlineThe first inequality gives us x > 0, and the second inequality gives us x5x \leq -5. Since these are connected by "or," we take the union of the two solutions.
  7. Express in Interval Notation: Express the solution in interval notation.\newlineThe solution to x > 0 is (0,)(0, \infty), and the solution to x5x \leq -5 is (,5](-\infty, -5]. Since we are looking for the union of these two solutions, the interval notation for the compound inequality is (,5](0,)(-\infty, -5] \cup (0, \infty).

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