What is the radius of the circle x^2 + y^2 - 64 = 0? Simplify any fractions. ____

Move Constant to Other Side: x^2 + y^2 - 64 = 0 Move the constant to the other side. Add 64 on both sides. x^2 + y^2 - 64 + 64 = 0 + 64 x^2 + y^2 = 64Find Value of r^2: x^2 + y^2 = 64 Find the value of r^2 compared to (x-h)^2 + (y-k)^2 = r^2. Standard form of a circle: (x-h)^2 + (y-k)^2 = r^2 Comparing the standard form and x^2 + y^2 = 64, we see that r^2 = 64.Solve for r: Solve for r. Take the square root of both sides. r = sqrt(r^2) r = sqrt(64) r = 8

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What is the radius of the circle $x^2 + y^2 - 64 = 0$ ? $\newline$ Simplify any fractions. $\newline$ ____ $\newline$

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Find properties of circles from equations in general form

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Q. What is the radius of the circle

x^2 + y^2 - 64 = 0

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Simplify any fractions.

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Move Constant to Other Side: $x^2 + y^2 - 64 = 0$ $\newline$ Move the constant to the other side. $\newline$ Add $64$ on both sides. $\newline$ $x^2 + y^2 - 64 + 64 = 0 + 64$ $\newline$ $x^2 + y^2 = 64$
Find Value of $r^2$ : $x^2 + y^2 = 64$ $\newline$ Find the value of $r^2$ compared to $(x-h)^2 + (y-k)^2 = r^2$ . $\newline$ Standard form of a circle: $(x-h)^2 + (y-k)^2 = r^2$ $\newline$ Comparing the standard form and $x^2 + y^2 = 64$ , we see that $r^2 = 64$ .
Solve for $r$ : Solve for $r$ . $\newline$ Take the square root of both sides. $\newline$ $r = \sqrt{r^2}$ $\newline$ $r = \sqrt{64}$ $\newline$ $r = 8$