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A circle in the 
xy-plane has the equation

x^(2)+y^(2)-10 x+32 y+272=0". "
Which of the following best describes the location of the center of the circle and the length of its radius?
Choose 1 answer:
(A) Center: 
(10,-32)
Radius: 
4sqrt17
(B) Center: 
(-10,32)
Radius: 
4sqrt17
(c) Center: 
(-5,16)
Radius: 3
(D) Center: 
(5,-16)
Radius: 3

A circle in the xy x y -plane has the equation\newlinex2+y210x+32y+272=0 x^{2}+y^{2}-10 x+32 y+272=0 \text {. } \newlineWhich of the following best describes the location of the center of the circle and the length of its radius?\newlineChoose 11 answer:\newline(A) Center: (10,32) (10,-32) \newlineRadius: 417 4 \sqrt{17} \newline(B) Center: (10,32) (-10,32) \newlineRadius: 417 4 \sqrt{17} \newline(C) Center: (5,16) (-5,16) \newlineRadius: 33\newline(D) Center: (5,16) (5,-16) \newlineRadius: 33

Full solution

Q. A circle in the xy x y -plane has the equation\newlinex2+y210x+32y+272=0 x^{2}+y^{2}-10 x+32 y+272=0 \text {. } \newlineWhich of the following best describes the location of the center of the circle and the length of its radius?\newlineChoose 11 answer:\newline(A) Center: (10,32) (10,-32) \newlineRadius: 417 4 \sqrt{17} \newline(B) Center: (10,32) (-10,32) \newlineRadius: 417 4 \sqrt{17} \newline(C) Center: (5,16) (-5,16) \newlineRadius: 33\newline(D) Center: (5,16) (5,-16) \newlineRadius: 33
  1. Start Completing the Square: Write the given equation of the circle and start completing the square for the xx and yy terms.\newlineThe given equation is x2+y210x+32y+272=0x^2 + y^2 - 10x + 32y + 272 = 0.\newlineTo complete the square for the xx terms, we need to find the value that makes x210xx^2 - 10x into a perfect square trinomial.\newlineThe value needed is (10/2)2=25(10/2)^2 = 25.\newlineSimilarly, for the yy terms, we need to find the value that makes y2+32yy^2 + 32y into a perfect square trinomial.\newlineThe value needed is (32/2)2=256(32/2)^2 = 256.
  2. Add Necessary Values: Add and subtract the necessary values to complete the square inside the equation.\newlineWe add 2525 to both sides for the xx terms and 256256 to both sides for the yy terms, and subtract these values outside the completed squares to keep the equation balanced.\newlineThe equation becomes x210x+25+y2+32y+256=272+25+256x^2 - 10x + 25 + y^2 + 32y + 256 = 272 + 25 + 256.
  3. Simplify the Equation: Simplify the equation by combining like terms and writing the completed squares.\newlineThe equation now is (x210x+25)+(y2+32y+256)=553(x^2 - 10x + 25) + (y^2 + 32y + 256) = 553.\newlineThis simplifies to (x5)2+(y+16)2=553(x - 5)^2 + (y + 16)^2 = 553.
  4. Compare to Standard Form: Compare the simplified equation to the standard form of a circle's equation.\newlineThe standard form of a circle's equation is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) is the center and rr is the radius.\newlineFrom our equation (x5)2+(y+16)2=553(x - 5)^2 + (y + 16)^2 = 553, we can see that the center (h,k)(h, k) is (5,16)(5, -16) and r2r^2 is 553553.
  5. Calculate the Radius: Calculate the radius of the circle.\newlineTo find the radius rr, we take the square root of 553553.\newlineThe radius rr is 553\sqrt{553}.\newlineHowever, 553553 is not a perfect square, so we need to simplify the square root.\newline553=17×32+9=17×33553 = 17 \times 32 + 9 = 17 \times 33.\newlineSo, the radius rr is 17×33=17×33\sqrt{17 \times 33} = \sqrt{17} \times \sqrt{33}.\newlineSince 33\sqrt{33} is not an integer, we cannot simplify further, and the radius remains 553\sqrt{553}.
  6. Identify Correct Answer: Identify the correct answer from the given options.\newlineThe center of the circle is (5,16)(5, -16), and the radius is 553\sqrt{553}.\newlineNone of the given options match this radius, so there must be a mistake in the calculation of the radius.

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