What is the radius of the circle x^2 + y^2 - 49 = 0? Simplify any fractions. ____

Move Constant: Move the constant to the other side to isolate the terms with x and y. Add 49 to both sides of the equation. x^2 + y^2 - 49 + 49 = 0 + 49 x^2 + y^2 = 49Identify Radius Squared: Identify the radius squared (r^2) from the equation. The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2, where r is the radius. Comparing x^2 + y^2 = 49 to the standard form, we see that r^2 = 49.Calculate Radius: Calculate the radius (r) by taking the square root of r^2. r = sqrt(49) r = 7

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What is the radius of the circle $x^2 + y^2 - 49 = 0$ ? $\newline$ Simplify any fractions. $\newline$ ____ $\newline$

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Q. What is the radius of the circle

x^2 + y^2 - 49 = 0

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Simplify any fractions.

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Move Constant: Move the constant to the other side to isolate the terms with $x$ and $y$ . Add $49$ to both sides of the equation. $x^2 + y^2 - 49 + 49 = 0 + 49$ $x^2 + y^2 = 49$
Identify Radius Squared: Identify the radius squared $r^2$ from the equation. $\newline$ The standard form of a circle is $(x-h)^2 + (y-k)^2 = r^2$ , where $r$ is the radius. $\newline$ Comparing $x^2 + y^2 = 49$ to the standard form, we see that $r^2 = 49$ .
Calculate Radius: Calculate the radius $r$ by taking the square root of $r^2$ . $r = \sqrt{49}$ $r = 7$