What is the percent error for a measurement of 2 milliliters? If needed, round your answer to the nearest hundredth of a percent. ____%

Find Error: Find the greatest possible error for 2 milliliters. Divide the smallest unit of measurement by 2. Since the problem does not specify the smallest unit of measurement, we will assume it is 1 milliliter, which is a common smallest unit for liquid measurements. 1/2 = 0.5 Greatest possible error: 0.5 millilitersCalculate Percent: Calculate the percent error. We have: Measurement: 2 milliliters Greatest possible error: 0.5 milliliters Percent error = (Greatest possible error / Measurement) × 100% Percent error = (0.5 / 2) × 100% Percent error = 0.25 × 100% Percent error = 25%Round Answer: Round the answer to the nearest hundredth of a percent if necessary. Since the percent error is exactly 25%, no rounding is needed.

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What is the percent error for a measurement of $2$ milliliters? $\newline$ If needed, round your answer to the nearest hundredth of a percent. $\newline$ $\newline$ $\_\_\_\%$

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Q. What is the percent error for a measurement of

2

milliliters?

\newline

If needed, round your answer to the nearest hundredth of a percent.

\newline

\newline

\_\_\_\%

Find Error: Find the greatest possible error for $2$ milliliters. $\newline$ Divide the smallest unit of measurement by $2$ . $\newline$ Since the problem does not specify the smallest unit of measurement, we will assume it is $1$ milliliter, which is a common smallest unit for liquid measurements. $\newline$ $\frac{1}{2} = 0.5$ $\newline$ Greatest possible error: $0.5$ milliliters
Calculate Percent: Calculate the percent error. $\newline$ We have: $\newline$ Measurement: $2$ milliliters $\newline$ Greatest possible error: $0.5$ milliliters $\newline$ Percent error = $(\text{Greatest possible error} / \text{Measurement}) \times 100\%$ $\newline$ Percent error = $(0.5 / 2) \times 100\%$ $\newline$ Percent error = $0.25 \times 100\%$ $\newline$ Percent error = $25\%$
Round Answer: Round the answer to the nearest hundredth of a percent if necessary. $\newline$ Since the percent error is exactly $25\%$ , no rounding is needed.