Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Avery is designing a large rectangular sign. They want the sign to have an area of 2m22\,\text{m}^2 and a width of 45m\frac{4}{5}\,\text{m}. How tall should the sign be?

Full solution

Q. Avery is designing a large rectangular sign. They want the sign to have an area of 2m22\,\text{m}^2 and a width of 45m\frac{4}{5}\,\text{m}. How tall should the sign be?
  1. Define height: Let hh be the height of the rectangular sign.\newlineWe know that the area of a rectangle is given by the formula Area=width×height\text{Area} = \text{width} \times \text{height}.
  2. Calculate area: Area of the rectangular sign: 2m22\,\text{m}^2\newlineWidth of the rectangular sign: 45m\frac{4}{5}\,\text{m}\newlineSubstitute the known values into the area formula to find the height.\newline2=(45)h2 = \left(\frac{4}{5}\right) \cdot h
  3. Find height using area formula: Solve for hh by dividing both sides of the equation by 45\frac{4}{5}.2(45)=(45)h(45)\frac{2}{\left(\frac{4}{5}\right)} = \frac{\left(\frac{4}{5}\right) \cdot h}{\left(\frac{4}{5}\right)}2(54)=h2 \cdot \left(\frac{5}{4}\right) = h2.5=h2.5 = h
  4. Solve for height: Calculate the height.\newline2×(54)=2.52 \times \left(\frac{5}{4}\right) = 2.5\newlineHeight of the rectangular sign: 2.52.5 m

More problems from Area and perimeter: word problems