What is the inverse of the function g(x)=-3(x+6)" ? " g^(-1)(x)=

Replace with y: To find the inverse of the function g(x) = -3(x + 6), we need to switch the roles of x and y and then solve for y. Let's start by replacing g(x) with y for clarity: y = -3(x + 6)Switch x and y: Now, switch x and y to find the inverse: x = -3(y + 6)Isolate y term: Next, we solve for y. Start by dividing both sides by -3 to isolate the term with y: x / -3 = y + 6Subtract 6: Now, subtract 6 from both sides to solve for y: y = (x / -3) - 6Replace with g^(-1)(x): Finally, we replace y with g^(-1)(x) to denote the inverse function: g^(-1)(x) = (x / -3) - 6

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What is the inverse of the function

g(x)=-3(x+6)" ? "

g^(-1)(x)=

What is the inverse of the function $\newline$ $\begin{array}{l} g(x)=-3(x+6) ? \\ g^{-1}(x)= \end{array}$

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Q. What is the inverse of the function

\newline

\begin{array}{l} g(x)=-3(x+6) ? \\ g^{-1}(x)= \end{array}

Replace with $y$ : To find the inverse of the function $g(x) = -3(x + 6)$ , we need to switch the roles of $x$ and $y$ and then solve for $y$ . Let's start by replacing $g(x)$ with $y$ for clarity: $y = -3(x + 6)$
Switch x and y: Now, switch x and y to find the inverse: $x = -3(y + 6)$
Isolate y term: Next, we solve for y. Start by dividing both sides by $-3$ to isolate the term with y: $\newline$ $\frac{x}{-3} = y + 6$
Subtract $6$ : Now, subtract $6$ from both sides to solve for $y$ : $y = \left(\frac{x}{-3}\right) - 6$
Replace with $g^{-1}(x)$ : Finally, we replace $y$ with $g^{-1}(x)$ to denote the inverse function: $\newline$ $g^{-1}(x) = \frac{x}{-3} - 6$