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Let’s check out your problem:
What is the factored form of
15
y
2
−
8
y
z
−
12
z
2
15y^2 - 8yz - 12z^2
15
y
2
−
8
yz
−
12
z
2
?
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Math Problems
Precalculus
Factor using a quadratic pattern
Full solution
Q.
What is the factored form of
15
y
2
−
8
y
z
−
12
z
2
15y^2 - 8yz - 12z^2
15
y
2
−
8
yz
−
12
z
2
?
Identify coefficients:
Identify the coefficients for factoring:
a
=
15
a = 15
a
=
15
,
b
=
−
8
b = -8
b
=
−
8
,
c
=
−
12
c = -12
c
=
−
12
.
Find two numbers:
Find two numbers that multiply to
a
c
ac
a
c
(
15
×
−
12
=
−
180
15 \times -12 = -180
15
×
−
12
=
−
180
) and add to
b
b
b
(
−
8
-8
−
8
). The numbers are
10
10
10
and
−
18
-18
−
18
.
Rewrite middle term:
Rewrite the middle term using the numbers found:
15
y
2
+
10
y
z
−
18
y
z
−
12
z
2
15y^2 + 10yz - 18yz - 12z^2
15
y
2
+
10
yz
−
18
yz
−
12
z
2
.
Factor by grouping:
Factor by grouping:
(
15
y
2
+
10
y
z
)
+
(
−
18
y
z
−
12
z
2
)
(15y^2 + 10yz) + (-18yz - 12z^2)
(
15
y
2
+
10
yz
)
+
(
−
18
yz
−
12
z
2
)
.
Factor out common terms:
Factor out the common terms from each group:
5
y
(
3
y
+
2
z
)
−
6
z
(
3
y
+
2
z
)
5y(3y + 2z) - 6z(3y + 2z)
5
y
(
3
y
+
2
z
)
−
6
z
(
3
y
+
2
z
)
.
Factor out common binomial:
Factor out the common binomial:
(
5
y
−
6
z
)
(
3
y
+
2
z
)
(5y - 6z)(3y + 2z)
(
5
y
−
6
z
)
(
3
y
+
2
z
)
.
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\newline
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