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What is the discriminant of the quadratic equation 
4x^(2)-7x+1=0 ?
33

-65

-33
65

What is the discriminant of the quadratic equation 4x27x+1=0 4 x^{2}-7 x+1=0 ?\newline3333\newline65 -65 \newline33 -33 \newline6565

Full solution

Q. What is the discriminant of the quadratic equation 4x27x+1=0 4 x^{2}-7 x+1=0 ?\newline3333\newline65 -65 \newline33 -33 \newline6565
  1. Identify Coefficients: The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. Let's identify the coefficients aa, bb, and cc from the given equation 4x27x+1=04x^2 - 7x + 1 = 0.
  2. Calculate Coefficients: The coefficient aa is the coefficient of x2x^2, which is 44. The coefficient bb is the coefficient of xx, which is 7-7. The coefficient cc is the constant term, which is 11.
  3. Plug into Formula: Now we will plug these values into the discriminant formula D=b24acD = b^2 - 4ac. So we have D=(7)24(4)(1)D = (-7)^2 - 4(4)(1).
  4. Calculate Discriminant: Calculating the discriminant, we get D=4916D = 49 - 16. We square 7-7 to get 4949 and multiply 44 by 44 and then by 11 to get 1616.
  5. Final Result: Subtracting 1616 from 4949, we get D=33D = 33. This is the value of the discriminant.

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