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What is the discriminant of the quadratic equation 
4x^(2)+4x+9=0 ?
128

-128

-160
160

What is the discriminant of the quadratic equation 4x2+4x+9=0 4 x^{2}+4 x+9=0 ?\newline128128\newline128 -128 \newline160 -160 \newline160160

Full solution

Q. What is the discriminant of the quadratic equation 4x2+4x+9=0 4 x^{2}+4 x+9=0 ?\newline128128\newline128 -128 \newline160 -160 \newline160160
  1. Identify coefficients: The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. Let's identify the coefficients aa, bb, and cc from the given equation 4x2+4x+9=04x^2 + 4x + 9 = 0.
  2. Calculate coefficients: The coefficient aa is the coefficient of x2x^2, which is 44. The coefficient bb is the coefficient of xx, which is 44. The coefficient cc is the constant term, which is 99.
  3. Substitute values: Now, let's calculate the discriminant using the formula D=b24acD = b^2 - 4ac. Substituting the values of aa, bb, and cc, we get D=(4)24(4)(9)D = (4)^2 - 4(4)(9).
  4. Perform calculations: Performing the calculations, we have D=164(4)(9)=16144D = 16 - 4(4)(9) = 16 - 144.
  5. Final result: Continuing with the calculation, we find D=16144=128D = 16 - 144 = -128.

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