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What is the discriminant of the quadratic equation 
4x^(2)-3x-5=0 ?

-71

-89
89
71

What is the discriminant of the quadratic equation 4x23x5=0 4 x^{2}-3 x-5=0 ?\newline71 -71 \newline89 -89 \newline8989\newline7171

Full solution

Q. What is the discriminant of the quadratic equation 4x23x5=0 4 x^{2}-3 x-5=0 ?\newline71 -71 \newline89 -89 \newline8989\newline7171
  1. Identify Coefficients: The discriminant of a quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. We need to identify the coefficients aa, bb, and cc from the given equation and then apply the formula.
  2. Given Quadratic Equation: The given quadratic equation is 4x23x5=04x^2 - 3x - 5 = 0. Here, the coefficient aa is 44, the coefficient bb is 3-3, and the coefficient cc is 5-5.
  3. Calculate Discriminant: Now we will calculate the discriminant using the formula D=b24acD = b^2 - 4ac. Substituting the values of aa, bb, and cc, we get D=(3)24(4)(5)D = (-3)^2 - 4(4)(-5).
  4. Final Result: Calculating the discriminant, we have D=94(4)(5)=9(80)=9+80=89D = 9 - 4(4)(-5) = 9 - (-80) = 9 + 80 = 89.

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